ThermodynamicsHard
Question
A refrigerator with coefficient of performance 1/3 releases 200 J of heat to a hot reservoir, then the work done on the working substance is :-
Options
A.
Joule
Joule B.100 Joule
C.
Joule
Joule D.150 Joule
Solution
β = 
Q2 = 50 Joule
W = Q1 - Q2 = 200 - 50 = 150 Joule
Q2 = 50 Joule
W = Q1 - Q2 = 200 - 50 = 150 Joule
Create a free account to view solution
View Solution FreeMore Thermodynamics Questions
Vrma′ Vav and Vmp are root mean squre, average and most probale speeds of molecules of a gas obeying Maxwellian ve...The temperature of 5 moles of a gas which was held at constant volume was changed from 100oC to 120oC. The change in int...The wavelength of maximum energy released during an atomic explosin was 2.93 × 10-10m. The maximum temperature atta...p-V plots for two gases during adiabatic processes are shown in the figure. Plots 1 and 2 should correspond respectively...three rods of identical cross-sectional area and made from the same material from the sides of an isoscales traangles AB...