ThermodynamicsHard
Question
A refrigerator with coefficient of performance 1/3 releases 200 J of heat to a hot reservoir, then the work done on the working substance is :-
Options
A.
Joule
Joule B.100 Joule
C.
Joule
Joule D.150 Joule
Solution
β = 
Q2 = 50 Joule
W = Q1 - Q2 = 200 - 50 = 150 Joule
Q2 = 50 Joule
W = Q1 - Q2 = 200 - 50 = 150 Joule
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