ThermodynamicsHard
Question
100 mole of an ideal monoatomic gas undergoes the following thermodynamic process as shown in the figure (P - V or Pressure - Volume plots are shown)
A → B : isothermal expansion
B → C : adiabatic expansion
C → D : isobaric compression
D → A : isochoric process
The heat transfer along the process AB is 9 × 104 J. The net work done by the gas during the cycle is (Take R = 8 J. K-1 mole-1)
A → B : isothermal expansion
B → C : adiabatic expansion
C → D : isobaric compression
D → A : isochoric process
The heat transfer along the process AB is 9 × 104 J. The net work done by the gas during the cycle is (Take R = 8 J. K-1 mole-1)
Options
A.- 0.5 × 104 J
B.+ 0.5 × 104 J
C.-5 × 104 J
D.+5 × 104 J
Solution
Wnet = WAB + WBC + WCD + WDA
= 9 × 104 +
+ P(V2 - V1) + 0
TB = TA = 300 K, TC =
= 9 × 104 +
+ 105( 1 - 2) + 0
= 5 × 104 joule
= 9 × 104 +
+ P(V2 - V1) + 0TB = TA = 300 K, TC =
= 9 × 104 +
+ 105( 1 - 2) + 0= 5 × 104 joule
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