Circular MotionHardBloom L2
Question
The magnitude of displacement of a particle moving in a circle of radius a with constant angular speed ω varies with time t as
Options
A.2a sin ωt
B.2a sin$\frac{\omega t}{2}$
C.2a cos ωt
D.2a cos $\frac{\omega t}{2}$
Solution
Sol.
$\Delta S = 2a\sin\frac{\theta}{2} = 2a\sin\frac{\omega t}{2}$
Create a free account to view solution
View Solution FreeMore Circular Motion Questions
A particle of mass m is suspended from a fixed point O by a string of length l. It is displaced by angle θ (θ ...A string og negligible mass going over a clamped pully of mass m support a block of mass M as shown in the figure. The f...The graphs below show angular velocity as a function of time. In which one is the magnitude of the angular acceleration ...The velocity and acceleration vectors of a particle undergoing circular motion are = 2î m/s and = 2î + 4ĵ...A stone tied to the end of string of 80 cm long. is whirled in a horizontal circle with a constant speed. If the stone m...