Circular MotionMedium
Question
If the equation for the displacement of a particle moving on a circular path is given as θ = 2 t3 + 0.5,
Where θ is in second. Then the angular velocity of the particle after two second will be:
Where θ is in second. Then the angular velocity of the particle after two second will be:
Options
A.36 red/sec
B.8 red/sec
C.48 red/sec
D.24 red/sec
Solution
θ = 2 t2 + 0.5
ω =
= 6t2 = 6 × 22
= 6 × 4 = 24radian/ sec
ω =
= 6t2 = 6 × 22= 6 × 4 = 24radian/ sec
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