Differential EquationHard

Question

The equation of the curve satisfying the differential equation y2 (x2 + 1) = 2xy1 passing through the point
(0, 1) and having slope of tangnet at x = 0 as 3, is

Options

A.y = x2 + 3x + 2y = x2 + 3x + 2
B.y2 = x2 + 3x + 1
C.y = x3 + 3x + 1
D.none of these

Solution

(x2 + 1) = 2x

⇒ ln = ln (x2 + 1) + ln c
⇒  = c(x2 + 1)  ⇒  c = 3  as at  x = 0,  = 3
= 3(x2 + 1) dx
⇒ y = x3 + 3x + 1

Create a free account to view solution

View Solution Free
Topic: Differential Equation·Practice all Differential Equation questions

More Differential Equation Questions