Chemical EquilibriumHard
Question
In a closed system : A(s) ⇋ 2B(g) + 3C(g), if the partial pressure of C is doubled at equilibrium, then partial pressure of B will be :
Options
A.two times the original value
B.one half of its original value
C.
times the original value
times the original valueD.2√2 times the original value
Solution
Kp = p2B(1)p3C(1) = p2B(2)p3C(2) = p2B(2)(2pC(1))3 ;
hence or
hence or
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