SHMHard

Question

In order that the resultant path on superimposing two mutually perpendicular SHMs be a circle, the condition is that

Options

A.The amplitude of both SHM should be equal and they should have a phase difference of π/2
B.The amplitude should be in the ratio 1 : 2 and the phase difference should be zero.
C.The amplitude should be in the ratio 1 : 2 and the phase difference should be π/2
D.The amplitude should be equal and the phase difference should be zero.

Solution

x = A cos ωt, y = B cos(ωt + φ)
If φ = & A = B ⇒ x2 + y2 = A2

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