ElectroMagnetic InductionHard
Question
A time varying voltage V = 2t volt is applied across an ideal inductor of inductance L = 2H as shown in figure. Then select incorrect statement
Options
A.current versus time graph is a parabola
B.energy stored in magnetic field at t = 2 s is 4J
C.potential energy at time t = 1 s in magnetic field is increasing at a rate of 1J/s
D.energy stored in magnetic field is zero all the time
Solution
V = 2t ⇒ L 
= 2t ⇒ 2 × = 2t ⇒ ⇒ i = 
⇒ i - t graph parabola
U =
Li2 = 
× 2 × 4 = 4J and 
= Li = 2 × 
× t = t3 = 1J/s
= 2t ⇒ 2 × = 2t ⇒ ⇒ i = ⇒ i - t graph parabolaU =
Li2 = × 2 × 4 = 4J and = Li = 2 × × t = t3 = 1J/sCreate a free account to view solution
View Solution FreeMore ElectroMagnetic Induction Questions
L,C and R represent physical quantities inductance, capacitance and resistance. The combination which has the dimensions...Consider the conducting square loop shown in fig. If the switch is closed and after some time it is opened again, the cl...Dimension of a ractangular coil is 20 cm × 10 cm. Number of turns in coil is 60. It is rotating about its one of th...A transformer connected to 220 volt line shows an output of 2A at 11000 volt. The efficiency is 100%. The current drawn ...In the circuit shown, the cell is ideal. the coil has an inductance of 4H and zero resistance. F is a fuse of zero resis...