ElectroMagnetic InductionHard
Question
A time varying voltage V = 2t volt is applied across an ideal inductor of inductance L = 2H as shown in figure. Then select incorrect statement
Options
A.current versus time graph is a parabola
B.energy stored in magnetic field at t = 2 s is 4J
C.potential energy at time t = 1 s in magnetic field is increasing at a rate of 1J/s
D.energy stored in magnetic field is zero all the time
Solution
V = 2t ⇒ L 
= 2t ⇒ 2 × = 2t ⇒ ⇒ i = 
⇒ i - t graph parabola
U =
Li2 = 
× 2 × 4 = 4J and 
= Li = 2 × 
× t = t3 = 1J/s
= 2t ⇒ 2 × = 2t ⇒ ⇒ i = ⇒ i - t graph parabolaU =
Li2 = × 2 × 4 = 4J and = Li = 2 × × t = t3 = 1J/sCreate a free account to view solution
View Solution FreeMore ElectroMagnetic Induction Questions
In a series L − R growth circuit, if maximum current and maximum induced emf in an inductor of inductance 3mH are ...A coil of 10-2 H inductance carries a current I = 2sin (100t) A. When current is half of its maximum value, then at that...A metal rod moves at a constant velocity in a direction perpendicular to its length. A constant uniform magnetic field e...Lenz′s law is based on :-...Two different coils have self-inductance L1 = 8 mH and L2 = 2mH. The current in one coil is increased at a constant rate...