ElectroMagnetic InductionMedium

Question

A time varying voltage V = 2t volt is applied across an ideal inductor of inductance L = 2H as shown in figure. Then select incorrect statement
                                 

Options

A.current versus time graph is a parabola
B.energy stored in magnetic field at t = 2 s is 4J
C.potential energy at time t = 1 s in magnetic field is increasing at a rate of 1J/s
D.energy stored in magnetic field is zero all the time

Solution

V = 2t ⇒ L = 2t ⇒ 2 × = 2t ⇒ ⇒ i = ⇒ i - t graph parabola
U = Li2 = × 2 × 4 = 4J and = Li = 2 × × t = t3 = 1J/s

Create a free account to view solution

View Solution Free
Topic: ElectroMagnetic Induction·Practice all ElectroMagnetic Induction questions

More ElectroMagnetic Induction Questions

The energy density in magnetic field B is proportional to :-...One conducting U tube can slide inside another as shown in figure, maintaining electrical contacts between the tubes. Th...A conducting ring lies fixed on a horizontal plane. If a charged nonmagnetic particle is released from a point (on the a...The flux linked with a coil at any instant ′t′ is given by φ = 10t2 - 50t + 250 The induced emf at t = ...A wire loop is rotated in magnetic field. The frequency of change of direction of the induced e.m.f. is :...