Set, Relation and FunctionHard

Question

If domain & range of function f(x) = are same, where a,b ∈ R & b > a, then -

Options

A.a = - 1 + √2, b = 2 - √2
B.a = 1 + √2, b = 2 - √2
C.a = - 1 - √2, b = 2 + √2
D.a = - 1 + √3, b = 2 - √3

Solution

Domain of f(x) is [a,b]
f′(x) = = 0 ⇒ x =
f(a) = f(b) = & f = √2
range is
⇒ b - a = a2 & 2(b - a)= b2
∵ a ≠ b
∴ (b2 - a2) = (b - a) ⇒ a + b = 1
⇒ a2 + 2a - 1 = 0
⇒ a = - 1 - √2 & b = 2 + √2 or a = - 1 + √2 & b = 2 - √2

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