Momentum and CollisionHard
Question
Two particles A and B of masses 2 m and m respectively are moving with same velocity v as shown in figure. At instant shown in figure, choose CORRECT option from the following :-
Options
A.Total kinetic energy of system (A + B) in the frame of centre of mass is 3mv2/2
B.Linear momentum of A in the frame of B has magnitude mv
C.Angular momentum of A in the frame of B has magnitude 2mvl
D.Angular velocity of line joining A and B has magnitude zero.
Solution
vbcm = v
ksys =
(2m)v2Ac + mv2Bc = 0
P = 2mvAB = 0
L = l(2m)vAB = 0
ksys =
(2m)v2Ac + mv2Bc = 0P = 2mvAB = 0
L = l(2m)vAB = 0
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