ProbabilityHard
Question
A kid want to put 5 different chocolates into his three different pockets. Let 
(in lowest terms) n, m ∈ N, denotes the probability of placing chocolates in such a manner that none of his pockets are empty.
Which of the following option(s) is/are correct ?
(in lowest terms) n, m ∈ N, denotes the probability of placing chocolates in such a manner that none of his pockets are empty. Which of the following option(s) is/are correct ?
Options
A.m is square of natural number
B.n is square of natural number
C.m - n = 31
D.m - n = 33
Solution
Either two pockets each have two chocolates & other pocket has 1 or two pockets each have one chocolate & other pocket has 3
∴ Number of ways
= 3C2 × 5C2 × 3C2 × 1 × 3C2 × 5C1 × 4C1
∴
∴ Number of ways
= 3C2 × 5C2 × 3C2 × 1 × 3C2 × 5C1 × 4C1
∴
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