CapacitanceMedium
Question
Two identical large thin metal plates carrying charges +q1 and +q2 (q1 > q2), respectively, are kept close at a distance d apart and parallel to each other to form a parallel plate capacitor of capacitance C. The potential difference between the plates is :
Options
A.(q1 − q2)/C
B.(q1 − q2)/(2C)
C.(q1 − q2)/(4C)
D.(q1 + q2)/(2C)
Solution
[Key Concept: For two isolated large plates the outer faces share the total charge equally, and only the inner-face charge sets the potential difference.]
$$\begin{matrix} & q_{3} = q_{1} - \frac{q_{1} + q_{2}}{2} = \left( \frac{q_{1} - q_{2}}{2} \right) \\ & Q = CV \\ & V = \frac{Q}{C} \\ & V = \left( \frac{q_{1} - q_{2}}{2} \right) \times \frac{1}{C} \\ & V = \frac{q_{1} - q_{2}}{2C} \end{matrix}$$
Create a free account to view solution
View Solution FreeMore Capacitance Questions
A thin semi-circular ring of radius r has a positive charge q distributed uniformly over it. The net field at the centre...A battery is used to charge a parallel plate capacitor till the potential difference between the plates becomes equal to...Two conducting spheres of radii R1 and R2 are charged with charges Q1 and Q2 respectively. On bringing them in contact t...In the given circuit, a charge of + 80μC is given to the upper plate of the 4μF capacitor. Then in the steady ...A capacitor is charged, now the battery is removed and a dielectric plate is entered, then choose the correct statement-...