Chemical Kinetics and Nuclear ChemistryMedium
Question
The rate of a reaction quadruples when temperature changes from $27^{\circ}C$ to $57^{\circ}C$. Calculate the energy of activation.
Given $R = 8.314\text{ }J{\text{ }K}^{- 1}{\text{ }mol}^{- 1},log4 = 0.6021$
Options
A.$3.80\text{ }kJ/mol$
B.$3804\text{ }kJ/mol$
C.$38.04\text{ }kJ/mol$
D.$380.4\text{ }kJ/mol$
Solution
Sol. [Key Concept: Activation energy from a temperature change]
$${log\left( \frac{k_{2}}{k_{1}} \right) = \frac{E_{a}}{2.303R}\left( \frac{1}{T_{1}} - \frac{1}{T_{2}} \right) }{log\left( \frac{4}{1} \right) = \frac{E_{a}}{2.303R}\left( \frac{1}{300} - \frac{1}{330} \right) }{E_{a} = \frac{(log(4)) \times 2.303 \times 8.314 \times 300 \times 330}{30} }{= 3.804 \times 10^{4}\text{ }J/mol }{= 38.04\text{ }kJ/mol }$$
Create a free account to view solution
View Solution FreeTopic: Chemical Kinetics and Nuclear Chemistry·Practice all Chemical Kinetics and Nuclear Chemistry questions
More Chemical Kinetics and Nuclear Chemistry Questions
Arrange the following in order of decreasing boiling point :-(I) n-butane (II) n-butanol (III) n-butyl chloride (IV) Iso...Aqueous ammonia can be used to separate which of the following pair of ions ?...is a stable isotope. is expressed to disintegrate by :...For the elementary reaction 2NO + O2 → 2NO2, the volume of a container is tripled. The rate becomes...The rate of the reaction 3A + 2B → Products is given by the rate expression rate = K[A][B]2. If A is taken in large exce...