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Question

The work done during reversible isothermal expansion of one mole of hydrogen gas at $25^{\circ}C$ from pressure of 20 atmosphere to 10 atmosphere is

(Given $R = 2.0calK^{- 1}{\text{ }mol}^{- 1}$ )

Options

A.413.14 calories
B.100 calories
C.0 calorie
D.-413.14 calories

Solution

Sol. [Key Concept: Reversible isothermal expansion work]

Using the chemistry sign convention and ideal gas behaviour,

w = −nRT ln(V₂/V₁) = −nRT ln(P₁/P₂).

Thus w = −1 × 2.0 × 298 × ln(20/10) ≈ −413.1 cal,

agreeing with option (4), −413.14 calories within rounding.

Expansion gives negative work on the system; work done by the gas has the opposite sign.

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