Carbonyl CompoundMedium
Question
Match List I with List II.
| List I (Reaction) | List II(Reagents/Condition) |
|---|---|
| A. |
I. |
| B. |
II. $\ {CrO}_{3}$ |
| C. |
III. ${KMnO}_{4}/KOH,\Delta$ |
| D. |
IV. (i) $O_{3}$(ii) $Zn - H_{2}O$ |
Choose the correct answer from the options given below:
Options
A.A-IV, B-I, C-II, D-III
B.A-I, B-IV, C-II, D-III
C.A-IV, B-I, C-III, D-II
D.A-III, B-I, C-II, D-IV
Solution
Sol. [Key Concept: Reagents for common organic transformations]
A–IV: reductive ozonolysis cleaves the C=C bond to give two cyclohexanone molecules. B–I: benzoyl chloride with anhydrous AlCl₃ acylates benzene to benzophenone. C–II: CrO₃ oxidises cyclohexanol to cyclohexanone. D–III: hot alkaline KMnO₄ oxidises the ethyl side chain to potassium benzoate. Therefore, option (1).
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