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Question

Given below are two statements:

Statement I: The boiling point of hydrides of Group 16 elements follow the order

$H_{2}O > H_{2}Te > H_{2}Se > H_{2}\text{ }S$.

Statement II: On the basis of molecular mass, $H_{2}O$ is expected to have lower boiling point than the other members of the group but due to the presence of extensive H -bonding in $H_{2}O$, it has higher boiling point.

In the light of the above statements, choose the correct answer from the options given below:

Options

A.Statement I is true but Statement II is false
B.Statement I is false but Statement II is true
C.Both Statement I and Statement II are true
D.Both Statement I and Statement II are false

Solution

Sol. [Key Concept: Boiling points of Group 16 hydrides]

Both statements are true. H₂O has an unusually high boiling point because of extensive intermolecular hydrogen bonding. Among H₂S, H₂Se and H₂Te, increasing size and polarisability strengthen dispersion attractions down the group.

The overall order is H₂O > H₂Te > H₂Se > H₂S, option (3).

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