Photosynthesis in Higher PlantsMedium
Question
How many molecules of ATP and NADPH are required for every molecule of ${CO}_{2}$ fixed in the Calvin cycle?
Options
A.3 molecules of ATP and 3 molecules of NADPH
B.3 molecules of ATP and 2 molecules of NADPH
C.2 molecules of ATP and 3 molecules of NADPH
D.2 molecules of ATP and 2 molecules of NADPH
Solution
Sol. [Key Concept: Energy cost of the Calvin cycle]
Fixing one CO₂ through the Calvin cycle requires 3 ATP and 2 NADPH. Accordingly, fixation of six CO₂ to produce the equivalent of one hexose requires 18 ATP and 12 NADPH. Hence, option (2).
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