Laws of MotionMedium
Question
A horizontal force 10 N is applied to a block $A$ as shown in figure. The mass of blocks $A$ and $B$ are 2 kg and 3 kg respectively. The blocks slide over a frictionless surface. The force exerted by block $A$ on block $B$ is :
Options
A.6 N
B.10 N
C.Zero
D.4 N
Solution
Sol. [Key Concept: Friction and equilibrium of connected blocks]
$$F = \left( M_{1} + M_{2} \right)a$$
$$\begin{matrix} a & \ = \frac{10}{2 + 3} = 2{\text{ }ms}^{- 2} \\ F^{'} & \ = M_{2}(2) = 3 \times 2\text{ }N = 6\text{ }N \end{matrix}$$
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