ElectrostaticsMedium
Question
A thin spherical shell is charged by some source. The potential difference between the two points $C$ and $P$ (in V) shown in the figure is:
(Take $\frac{1}{4\pi\varepsilon_{0}} = 9 \times 10^{9}$ SI units)
Options
A.$0.5 \times 10^{5}$
B.Zero
C.$3 \times 10^{5}$
D.$1 \times 10^{5}$
Solution
Sol. [Key Concept: Charged spherical shell — potential inside vs outside]
For uniformly charged spherical shell,
$$\begin{matrix} & V = \frac{kq}{R}\ \ (\text{~}\text{For}\text{~}r \leq R) \\ \therefore\ & V_{C} = V_{P} \\ & V_{C} - V_{P} = \text{~}\text{Zero}\text{~} \end{matrix}$$
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