Question
Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R.
Assertion A: The potential ( $V$ ) at any axial point, at 2 m distance ( $r$ ) from the centre of the dipole of dipole moment vector $\overrightarrow{P}$ of magnitude, $4 \times 10^{- 6}Cm$, is $\pm 9 \times 10^{3}\text{ }V$.
(Take $\frac{1}{4\pi\epsilon_{0}} = 9 \times 10^{9}$ SI units)
Reason R: $V = \pm \frac{2P}{4\pi\epsilon_{0}r^{2}}$, where $r$ is the distance of any axial point, situated at 2 m from the centre of the dipole.
In the light of the above statements, choose the correct answer from the options
given below:
Options
Solution
Sol. [Key Concept: Assertion–Reason evaluation]
The potential $V$ at any point, at distance $r$ from centre of dipole $= \frac{KPcos\theta}{r^{2}}$
At axial point where $\theta = 0^{\circ},V = \frac{KP}{r^{2}} = \frac{9 \times 10^{9} \times 4 \times 10^{- 6}}{2^{2}} = 9 \times 10^{3}\text{ }V$
At axial point where $\theta = 180^{\circ},V = \frac{- KP}{r^{2}} = - 9 \times 10^{3}\text{ }V$
Create a free account to view solution
View Solution Free