ElectroMagnetic InductionMedium
Question
In an ideal transformer, the turns ratio is $\frac{N_{P}}{N_{S}} = \frac{1}{2}$. The ratio $V_{S}:V_{P}$ is equal to (the symbols carry their usual meaning) :
Options
A.$1:1$
B.$1:4$
C.$1:2$
D.$2:1$
Solution
Sol. [Key Concept: Ideal transformer — Vs/Vp = Ns/Np]
According to transformer ratio,
$$\frac{V_{S}}{V_{P}} = \frac{N_{S}}{N_{P}} = 2:1$$
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