GravitationMedium
Question
The minimum energy required to launch a satellite of mass $m$ from the surface of earth of mass $M$ and radius $R$ in a circular orbit at an altitude of $2R$ from the surface of the earth is:
Options
A.$\frac{GmM}{2R}$
B.$\frac{GmM}{3R}$
C.$\frac{5GmM}{6R}$
D.$\frac{2GmM}{3R}$
Solution
Sol. [Key Concept: Energy to launch a satellite (binding energy)]
Apply energy conservation,
$$U_{i} + K_{i} = U_{f} + K_{f}$$
$$\begin{matrix} & \ \Rightarrow \ - \frac{GMm}{R} + K_{i} = - \frac{GMm}{3R} + \frac{1}{2}mv^{2} \\ & \ \Rightarrow \ - \frac{GMm}{R} + K_{i} = - \frac{GMm}{3R} + \frac{1}{2} \times m \times \frac{GM}{3R} \\ & \ \Rightarrow \ K_{i} = - \frac{1}{6}\frac{GMm}{R} + \frac{GMm}{R} \end{matrix}$$
$$K_{i} = \frac{5}{6}\frac{GMm}{R}$$
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