Geometrical OpticsMedium
Question
A small telescope has an objective of focal length 140 cm and an eye piece of focal length 5.0 cm . The magnifying power of telescope for viewing a distant object is:
Options
A.17
B.32
C.34
D.28
Solution
Sol. [Key Concept: Telescope — magnifying power = fₒ/fₑ]
$f_{0} = 140\text{ }cm$ and $f_{e} = 5\text{ }cm$
For distant object,
$$m = \frac{f_{0}}{f_{e}} = \frac{140}{5} = 28$$
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