ElectroMagnetic InductionMedium

Question

Consider a long solenoid of length $I$ and radius $r$. If $n$ is the number of turns per unit length and $\mu_{0}$ is the permeability of free space, the inductance of the solenoid is :

Options

A.$\left( \mu_{0}/2\pi \right)n^{2}r^{2}/$
B.$2\mu_{0}\pi n^{2}r^{2}l$
C.$\mu_{0}\pi n^{2}r^{2}/$
D.$\mu_{0}n^{2}r^{2}l$

Solution

Sol. [Key Concept: Self-inductance of a long solenoid]

Self inductance of solenoid

$$\begin{matrix} & L = \frac{N\phi}{i} \\ & L = \frac{NBA}{i} \\ & L = \frac{N\mu_{0}niA}{i}\left\lbrack n = \frac{N}{I} \right\rbrack \\ & L = N\mu_{0}nA \\ & L = \left( \frac{N}{I} \right)\mu_{0}nAl \\ & L = \mu_{0}n^{2}Al \\ & L = \mu_{0}n^{2}\pi r^{2}l\ \left\lbrack \because A = \pi r^{2} \right\rbrack \end{matrix}$$

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