Question
For sound waves, if the number of nodes for the $5^{\text{th}\text{~}}$ harmonic of an open-ended pipe is $n$ and that for the $9^{\text{th}\text{~}}$ harmonic of the same pipe with one of its ends closed is $m$, the ratio $\frac{n}{m}$ is
Options
Solution
Sol. [Key Concept: Standing waves — harmonics in pipes]
For open organ pipe
- Number of nodes are same as number of harmonics
$$\ \therefore\ n = 5$$
For closed organ pipe
- There are only odd harmonics
For $1^{\text{st}\text{~}}$ harmonic → Number of nodes → 1
For $3^{\text{rd}\text{~}}$ harmonic → Number of nodes → 2
For $5^{\text{th}\text{~}}$ harmonic → Number of nodes → 3
For $7^{\text{th}\text{~}}$ harmonic → Number of nodes → 4
For $9^{\text{th}\text{~}}$ harmonic → Number of nodes → 5
$$\ \therefore\ m = 5 $$→ $\frac{n}{m} = \frac{5}{5} = 1$
Create a free account to view solution
View Solution Free