Sound WavesMedium

Question

For sound waves, if the number of nodes for the $5^{\text{th}\text{~}}$ harmonic of an open-ended pipe is $n$ and that for the $9^{\text{th}\text{~}}$ harmonic of the same pipe with one of its ends closed is $m$, the ratio $\frac{n}{m}$ is

Options

A.1
B.$\frac{3}{5}$
C.$\frac{5}{9}$
D.$\frac{9}{5}$

Solution

Sol. [Key Concept: Standing waves — harmonics in pipes]

For open organ pipe

- Number of nodes are same as number of harmonics

$$\ \therefore\ n = 5$$

For closed organ pipe

- There are only odd harmonics

For $1^{\text{st}\text{~}}$ harmonic → Number of nodes → 1

For $3^{\text{rd}\text{~}}$ harmonic → Number of nodes → 2

For $5^{\text{th}\text{~}}$ harmonic → Number of nodes → 3

For $7^{\text{th}\text{~}}$ harmonic → Number of nodes → 4

For $9^{\text{th}\text{~}}$ harmonic → Number of nodes → 5

$$\ \therefore\ m = 5 $$→ $\frac{n}{m} = \frac{5}{5} = 1$

Create a free account to view solution

View Solution Free
Topic: Sound Waves·Practice all Sound Waves questions

More Sound Waves Questions