SemiconductorMedium
Question
An ideal Zener diode with breakdown voltage of -3 V is reverse biased with a negative input voltage $V_{i} = - 5\text{ }V$. The magnitude of voltage difference between point $B$ and $A$ is:
Options
A.1 V
B.0 V
C.3 V
D.2 V
Solution
Sol. [Key Concept: Zener diode as a voltage regulator (reverse breakdown)]
$$\begin{matrix} & \left| V_{\text{input}\text{~}} \right|(5\text{ }V) > \left| V_{\text{zener}\text{~}} \right|(3\text{ }V) \\ & V_{\text{zener}\text{~}} = 3\text{ }V \\ & V_{\text{Total}\text{~}} = 5\text{ }V \\ & \ \therefore\left| V_{BA} \right| = (5 - 3) = 2\text{ }V \end{matrix}$$
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