Redox and Equivalent ConceptMedium
Question
The correct decreasing order of oxidation state of the underlined atom in each molecule is
Options
A.${\underline{PbO}}_{2} > {\underline{N}}_{2}O_{3} > {\underline{SO}}_{3}$
B.${\underline{P}}_{4}O_{6} > {\underline{Cl}}_{2}O_{7} > {\underline{AlH}}_{3}$
C.$\ {\underline{P}}_{4}O_{10} > {\underline{SO}}_{3} > H_{2}\underline{O}$
D.${\underline{N}}_{2}O_{5} > {\underline{Al}}_{2}O_{3} > H_{2}\underline{\text{ }S}$
Solution
Sol. [Key Concept: Assigning oxidation states]
${\underline{P}}_{4}^{+ 3}O_{6},{\underline{Cl}}_{2}O_{7},{\overset{+ 3}{AlH}}_{3}$
$$\begin{matrix} & {\underline{P}}_{4}^{5}O_{10},{\underline{SO}}_{3}^{+ 6},H_{2}\underline{O} \\ & {\underline{\text{ }N}}_{2}^{+ 5}O_{5},{\underline{Al}}_{2}^{+ 3}O_{3},H_{2}\underline{\text{ }S} \\ & {\underline{\text{ }Pb}}_{2}^{+ 4},{\text{ }N}_{2}^{+ 3}O_{3},\overset{+ 6}{\text{ }S}O_{3} \end{matrix}$$
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