Question
Given below are two statements:
Statement-I: Oxidation of p-nitrotoluene with acidic ${KMnO}_{4}$ gives an acid that is stronger than benzoic acid.
Statement-II: Reduction of p-nitrotoluene with Sn/HCl followed by neutralization gives an amine that is more basic than aniline.
In light of the above statements, choose the most appropriate answer from the options given below.
Options
Solution
Sol. [Key Concept: Oxidation of substituted toluenes]
• Oxidation of p-nitrotoluene with acidic ${KMnO}_{4}$ converts into p-nitrobenzoic acid.
because of -I effect and -M effect, making p-nitrobenzoic acid as stronger acid than benzoic acid.
- Reduction of p-nitrotoluene with Sn/HCl followed by neutralization reduces the $\left( - {NO}_{2} \right)$ to an amino group $\left( - {NH}_{2} \right)$, forming p-toluidine.
i.e., p -methylaniline is more basic than aniline due to the +I effect and hyperconjugation.
Create a free account to view solution
View Solution Free