Fluid MechanicsMedium
Question
A submarine is designed to withstand an absolute pressure of 100 atm. How deep can it go below the water surface?
(Consider the density of water $= 1000\text{ }kg{\text{ }m}^{- 3}$,
$1\text{ }atm = 1 \times 10^{5}\text{ }Pa$ and gravitational acceleration $g = 10\text{ }m/s^{2}$ )
Options
A.990 m
B.9900 m
C.99 m
D.9000 m
Solution
Sol. [Key Concept: Fluid pressure with depth: P = P₀ + ρgh] $P = P_{0} + \rho gh$
$$\begin{matrix} & \ \Rightarrow 100 \times 10^{5} = 10^{5} + 10^{3} \times 10 \times h \\ & \ \Rightarrow 10^{7} = 10^{5} + 10^{4}h \\ & \ \Rightarrow 10^{3} = 10 + h \\ & \ \Rightarrow h = 1000 - 10 = 990\text{ }m \end{matrix}$$
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