CapacitanceMedium
Question
Consider two uncharged capacitors of equal capacitance 200 pF. One of them is charged by a 100 V supply and disconnected. Now this capacitor is connected to the uncharged capacitor. The amount of electrostatic energy lost in the process is:
Options
A.$0.5 \times 10^{- 6}\text{ }J$
B.1.0 J
C.$1.0 \times 10^{- 6}\text{ }J$
D.0.5 J
Solution
Sol. [Key Concept: Newton's second law — resultant of ⟂ forces] Energy loss $= \frac{1}{2}\frac{C_{1}C_{2}}{C_{1} + C_{2}}V^{2}$
$$\begin{matrix} & \ = \frac{1}{2}\left( \frac{200 \times 200}{400} \right) \times 10^{- 12}(100)^{2} \\ & \ = \frac{1}{2} \times 10^{6} \times 10^{- 12} = 0.5 \times 10^{- 6}\text{ }J \end{matrix}$$
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