Current Electricity and Electrical InstrumentMedium
Question
A resistor is connected to a battery of 12 V emf and internal resistance $2\Omega$. If the current in the circuit is 0.6 A, the terminal voltage of the battery is:
Options
A.10 V
B.1.2 V
C.12 V
D.10.8 V
Solution
Sol. [Key Concept: Terminal voltage V = ε − I·r] Circuit can be draw as,
⇒ Terminal voltage of battery
$$V = E - ir = 12 - 0.6 \times 2 = 10.8\text{ }V$$
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