Redox and Equivalent ConceptMedium
Question
Consider the following compounds :
${\underline{KO}}_{2},H_{2}{\underline{O}}_{2}$ and $H_{2}{\underline{SO}}_{4}$
The oxidation state of the underlined elements in them are, respectively,
Options
A.$+ 1, - 1$, and +6
B.$\ + 2, - 2$, and +6
C.$+ 1, - 2$, and +4
D.$+ 4, - 4$, and +6
Solution
Sol. [Key Concept: Oxidation states of the underlined elements (KO₂, H₂O₂, H₂SO₄)]
${KO}_{2} \rightarrow$ Alkali metal always shows +1 oxidation state. Therefore, oxidation state of K is +1 .
Create a free account to view solution
View Solution FreeMore Redox and Equivalent Concept Questions
The equivalent volume of a gaseous substance is 5.6 L at 0o C and 1 atm. The substance may be...Ge (II) compounds are powerful reducing agents whereas Pb (IV)compounds are strongoxidants. It can be due to....In the reaction, P4 + NaOH + H2O → PH3 + NaH2PO2, the equivalent weight of P4 is...The oxidation states of the most electronegative element in the products of the reaction, BaO2 with dil. H2SO4 are...Which of the following statements is true about oxidation state of S in Na2S4O6?...