Dynamics and StatisticsMedium
Question
The mean deviation about the mean for the data
| $$x_{i}$$ | 5 | 7 | 9 | 10 | 12 | 15 |
|---|---|---|---|---|---|---|
| $$f_{i}$$ | 8 | 6 | 2 | 2 | 2 | 6 |
is equal to :
Options
A.$\frac{40}{13}$
B.$\frac{42}{13}$
C.$\frac{44}{13}$
D.$\frac{46}{13}$
Solution
Sol. [Key Concept: Mean $m = \frac{\sum\ f_{i}x_{i}}{\sum\ f_{i}}$, then mean deviation $= \frac{\sum\ f_{i}{|x}_{i} - m|}{\sum\ f_{i}}$.]
M.D. $= \frac{\sum f_{i}\left| x_{i} - \bar{x} \right|}{\sum f_{i}}$
$${\bar{x} = \frac{\sum f_{i}x_{i}}{\sum f_{i}} = \frac{40 + 42 + 18 + 20 + 24 + 90}{26} }{= \frac{234}{26} = 9 }$$M.D. $= \frac{8(4) + 6(2) + 2(0) + 2(1) + 2(3) + 6(6)}{26}$
$$= \frac{84}{26} = \frac{44}{13} $$
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