HydrocarbonsMedium
Question
Methane reacts with steam at 1273 K in the presence of nickel catalyst to form:
Options
A.CO and $H_{2}O$
B.${CO}_{2}$ and $H_{2}$
C.$CO$ and $H_{2}$
D.${CO}_{2}$ and $H_{2}O$
Solution
Sol. [Key Concept: Steam reforming of methane → syngas (CO + H2)]
$${{CH}_{4}(\text{ }g) + H_{2}O(\text{ }g)\underset{\phantom{(1273\text{ }K)\ }}{\overset{\phantom{Ni\ }}{\rightarrow}}CO + 3H_{2} } {(Used\ for\ industrial\ preparation\ of\ dihydrogen\ gas)}$$
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