ProbabilityHardBloom L3

Question

If two squares are chosen at random on a chess board, then find the probability so that

Options

A.they have a side common is $\frac{1}{9}$
B.they have a side common is $\frac{1}{18}$
C.they have contact at a corner is $\frac{7}{144}$
D.they have contact at a corner is $\frac{7}{72}$

Solution

Sol. [Key Concept: Two squares on a chessboard: split into same-row, same-column and diagonal cases.]

(a) $\frac{7 \times 8 + 7 \times 8}{\ ^{64}C_{2}} = \frac{7 \times 8 \times 2 \times 2}{64 \times 63} = \frac{1}{18}$

(b) $p = \frac{7 \times 7 + 7 \times 7}{\ ^{64}C_{2}} = \frac{2 \times 7 \times 7 \times 2}{64 \times 63} = \frac{7}{144}$

Alternate: (a)

$$= \frac{1 + 9 + 1}{8 \times 63} = \frac{1 + 9 + 1}{2 \times 9} = \frac{1}{18}$$

(b) $\frac{36 \times 4 + 24 \times 2 + 4 \times 1}{64 \times 63} = \frac{7}{144}$

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