ProbabilityHardBloom L3
Question
A bag contains three white, two blue and four red balls. If four balls are drawn one by one with replacement, then the probability that sample contains just one white ball is
Options
A.$\frac{16}{81}$
B.$\frac{8}{81}$
C.$\frac{32}{81}$
D.$\frac{64}{81}$
Solution
Sol. [Key Concept: Bag 3W+2Blue+4R: probability of the stated colour event.]
$$P = \ ^{4}C_{1}\left( \frac{3}{9} \right)\left( \frac{6}{9} \right)^{3} = \frac{32}{81}$$
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