Question
A certain kind of bacteria either die, split into two or split into three bacteria. All splits are exact copies. The probability of dying is $\frac{1}{4}$, the probability of splitting into two is $\frac{1}{2}$ and splitting into three is $\frac{1}{4}$.
The probability that it survives for infinite length of time is
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Solution
Sol. [Key Concept: Bacteria die/split: solve the fixed-point equation for survival.]
Let probability of single bacteria to die $= P$
$$\therefore\ P = \frac{1}{4} \times 1 + \frac{1}{2} \times P \times P + \frac{1}{4} \times P \times P \times P$$
bacteria die or split
A → bacteria do not split
B → bacteria split into 2
$C \rightarrow$ bacteria split into 3
D → bacterial die
$$\begin{matrix} & & \ \ \ \ \ \ \ \ & P(D) & \ = P(D \cap \text{ }A) + P(D \cap \text{ }B) + P(D \cap C) \\ & & \ \ \ \ \ \ \ \ & P & \ = \frac{1}{4} \times 1 + \frac{1}{2} \times P \times P + \frac{1}{4} \times P \times P \times P \\ & \ \Rightarrow & \ \ \ \ \ \ \ \ & P^{3} + 2P^{2} - 4P + 1 & \ = 0 \\ & \ \Rightarrow & \ \ \ \ \ \ \ \ & \ (P - 1)\left( P^{2} + 3P - 1 \right) & \ = 0 \\ & \ \Rightarrow & \ \ \ \ \ \ \ \ & P & \ = \frac{- 3 + \sqrt{13}}{2} \end{matrix}$$
∴ Probability that bacteria survive
$$= 1 - \frac{\sqrt{13} - 3}{2} = \frac{5 - \sqrt{13}}{2}$$
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