Progression (Sequence and Series)HardBloom L3

Question

If $x,y,z$ are three distinct positive real numbers and are in H.P., then $\frac{3x + 2y}{2x - y} + \frac{3z + 2y}{2z - y}$ is greater than

Options

A.9
B.10
C.12
D.15

Solution

Sol. [Key Concept: $a,b,c$ distinct positive in H.P. ⇒ A.M.–G.M.–H.M. inequalities give the bounds.]

$$\frac{3x + \frac{4xz}{x + z}}{2x - \frac{2xz}{x + z}} + \frac{3z + \frac{4xz}{x + z}}{2z - \frac{2xz}{z + x}} = \frac{3x^{2} + 7xz}{2x^{2}} + \frac{7xz + 3z^{2}}{2z^{2}}$$

$$= 3 + \frac{7}{2}\left( \frac{z}{x} + \frac{x}{z} \right) \in (10,\infty)$$

✔ (a) expression $\in (10,\infty)$, so always $> 9$

✔ (b) always $> 10$

✘ (c) can be just above 10, $< 12$

✘ (d) can be $< 15$

Create a free account to view solution

View Solution Free
Topic: Progression (Sequence and Series)·Practice all Progression (Sequence and Series) questions

More Progression (Sequence and Series) Questions