Progression (Sequence and Series)HardBloom L3

Question

A G.P. consist of an even number of terms. If the sum of all the terms is 5 times the sum of the terms occupying the odd places. Then the common ratio will be equal to

Options

A.3
B.4
C.5
D.6

Solution

Sol. [Key Concept: G.P. with even count: sum $= 5 \times$ (odd-place sum) ⇒ a relation in the common ratio.]

Let $a,ar,{ar}^{2},\ldots\ldots{ar}^{2n - 1}$

$$\begin{matrix} & & \frac{a\left( 1 - r^{2n} \right)}{1 - r} & = \frac{5a\left( 1 - \left( r^{2} \right)^{n} \right)}{1 - r^{2}} \\ \Rightarrow & & & r = 4 \end{matrix}$$

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