Human Health and DiseaseMedium
Question
With the help of given pedigree, find out the probability for the birth of a child having no disease and being a carrier (has the disease mutation in one allele of the gene) in $F_{3}$ generation.
Options
A.$1/4$
B.$1/2$
C.$1/8$
D.Zero
Solution
As in the $F_{1}$ generation the carrier female and non-affected (normal, not carrier) had affected male child that means the genetic disorder is sex-linked recessive.
The consanguineous mating between female ( $X^{c}X$ ) and male ( $X^{c}Y$ )
| $$O^{O}$$ | $$X^{c}$$ | Y |
|---|---|---|
| $$X^{c}$$ | $$X^{c}X^{c}$$ | $$X^{c}Y$$ |
| X | $$X^{c}X$$ | XY |
Out of 4 child only one is carrier i.e. $\frac{1}{4}$.
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