SemiconductorMedium

Question

The output $(Y)$ of the given logic implementation is similar to the output of an/a $\_\_\_\_$ gate.

Options

A.AND
B.NAND
C.OR
D.NOR

Solution

$$\begin{matrix} & Y_{1} = \overline{A + B} \\ & Y_{2} = \overline{A \cdot B} \\ & Y = Y_{1} \cdot Y_{2} \\ & \ = \overline{A + B \cdot}\overline{A \cdot B} \\ & \ = \overline{(A + B) + A \cdot B} \\ & \ = \overline{A + B(1 + A)} \\ & \ = \overline{A + B}\ \text{~}\text{NOR gate}\text{~} \end{matrix}$$

Create a free account to view solution

View Solution Free
Topic: SemiconductorยทPractice all Semiconductor questions

More Semiconductor Questions