Straight LineHardBloom L3
Question
The area enclosed by the graphs of $|x + y| = 2$ and $|x| = 1$ is:
Options
A.2
B.4
C.6
D.8
Solution
Sol. [Key Concept: $|x + y| = 2$ and $|x| = 1$ bound a parallelogram; area $=$ base $\times$ height.]
Figure is a parallelogram
Area $= 2\left( \frac{1 + 3}{2} \cdot 2 \right) = 8$
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