Straight LineHardBloom L3
Question
Area of the triangle formed by the line $x + y = 3$ and angle bisector of the pair of straight lines $x^{2} - y^{2} + 2y - 1 = 0$ is :
Options
A.2 sq. units
B.4 sq. units
C.6 sq. units
D.8 sq. units
Solution
Sol. [Key Concept: The angle bisectors of $x^{2 -}y^{2 + 2}y - 1 = 0$ are $x =$const lines; area cut by $x + y = 3$.]
$PAB$ is the required triangle.
∴ Area of $\bigtriangleup PAB = \frac{1}{2} \times 2 \times 2 = 2$
Create a free account to view solution
View Solution FreeMore Straight Line Questions
If x1, x2, x3 and y1, y2, y3 are both in G.P. with the same common ratio, then the points (x1, y1) (x2, y2) and (x3, y3)...The angle between the lines y − x + 5 = 0 and √3 x − y + 7 = 0 is -...If the vertices P, Q, R a triangle PQR are rational points, which of the golloeing points of the triangle PQR is / (are)...If (0, 0), (−2, 1) and (5, 2) are the vertices of a triangle, Then equation of line passing through its centroid a...The foot of the perpendicular drawn from the point (7, 8) to the line 2x + 3y − 4 = 0 is -...