Straight LineHardBloom L3
Question
If $( - 2,6)$ is the image of the point $(4,2)$ with respect to the line $L = 0$, then $L$ is equal to :
Options
A.$3x - 2y + 11 = 0$
B.$2x - 3y + 11 = 0$
C.$3x - 2y + 5 = 0$
D.$6x - 4y + 1 = 0$
Solution
Sol. [Key Concept: Image of a point in a line: $\frac{x - x_{1}}{a} = \frac{y - y_{1}}{b} = \frac{- 2({ax}_{1 +}{by}_{1 +}c)}{a^{2 +}b^{2}}$.]
Equation of $L$ is
$$\begin{matrix} & y - 4 = \frac{3}{2}(x - 1) \\ & 2y - 8 = 3x - 3 \\ \Rightarrow & 3x - 2y + 5 = 0 \end{matrix}$$
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