HyperbolaHardBloom L3
Question
The equation(s) to common tangent(s) to the two hyperbola $\frac{x^{2}}{a^{2}} - \frac{y^{2}}{b^{2}} = 1$ and $\frac{y^{2}}{a^{2}} - \frac{x^{2}}{b^{2}} = 1$ is/are:
Options
A.$y = x + \sqrt{a^{2} - b^{2}}$
B.$y = x - \sqrt{a^{2} - b^{2}}$
C.$y = - x + \sqrt{a^{2} - b^{2}}$
D.$y = - x - \sqrt{a^{2} - b^{2}}$
Solution
Sol. (a, b, c, d)
Equation of tangent of $\frac{x^{2}}{a^{2}} - \frac{y^{2}}{b^{2}} = 1$
$$\begin{array}{r} y = mx \pm \sqrt{a^{2}m^{2} - b^{2}}\#(1) \end{array}$$
∵ (1) is tangent to $\frac{x^{2}}{\left( - b^{2} \right)} - \frac{y^{2}}{\left( - a^{2} \right)} = 1$
$${\Rightarrow a^{2}m^{2} - b^{2} = - b^{2}m^{2} - \left( - a^{2} \right) }{\Rightarrow m^{2} = 1 }$$∴ Equation of common tangents are $y = \pm x \pm \sqrt{a^{2} - b^{2}}$
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