EllipseHardBloom L3
Question
The locus of point of intersection of perpendicular tangents of ellipse $\frac{(x - 1)^{2}}{16} + \frac{(y - 1)^{2}}{9} = 1$ is:
Options
A.$x^{2} + y^{2} = 25$
B.$x^{2} + y^{2} + 2x + 2y - 23 = 0$
C.$x^{2} + y^{2} - 2x - 2y - 23 = 0$
D.none of these
Solution
Sol.(c) Locus is director circle given by
$$\Rightarrow \ x^{2} + y^{2} - 2x - 2y - 23 = 0$$
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