ParabolaHardBloom L3

Question

Two mutually perpendicular tangents of the parabola $y^{2} = 4ax$ meet its axis in $P_{1}$ and $P_{2}$. If $S$ is the focus of the parabola then $\frac{1}{SP_{1}} + \frac{1}{SP_{2}}$ is equal to :

Options

A.$\frac{4}{a}$
B.$\frac{2}{a}$
C.$\frac{1}{a}$
D.$\frac{1}{4a}$

Solution

Sol. [Key Concept: Tangent at $t$ meets the axis with $SP = a(1 + t^{2})$; perpendicular tangents have $t_{1}t_{2} = - 1$, giving $\frac{1}{{SP}_{1}} + \frac{1}{{SP}_{2}} = \frac{1}{a}$.]

$\begin{matrix} \frac{1}{a + at_{1}^{2}} + \frac{1}{a + at_{2}^{2}} & \ = \frac{1}{a + at_{1}^{2}} + \frac{1}{a + a\left( - \frac{1}{t_{1}} \right)^{2}} \\ & \ \end{matrix}$

$$= \frac{1}{a}$$

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