CircleHardBloom L3
Question
The equation(s) of the tangent at the point ( 0,0 ) to the circle, making intercepts of lengths $2a$ and $2b$ units on the coordinates axes, is/are:
Options
A.$ax + by = 0$
B.$ax - by = 0$
C.$x = y$
D.$bx + ay = 0$
Solution
Sol. [Key Concept: A circle through the origin making intercepts $2a,2b$ on the axes has the form $x^{2} + y^{2} - 2ax - 2by = 0$ (signs vary); the tangent at $O$ is $ax + by = 0$.]
Eqn. of circle is
$$\left( x \pm a^{2} \right) + (y \pm b)^{2} = a^{2} + b^{2} $$or $(x \pm b)^{2} + (y \pm a)^{2} = a^{2} + b^{2}$
$$x^{2} + y^{2} \pm 2ax \pm 2by = 0 $$or $x^{2} + y^{2} \pm 2bx \pm 2ay = 0$
Eqn. of tangent origin is
$$ax \pm by = 0\ \text{~}\text{or}\text{~}\ bx \pm ay = 0$$
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