CircleHardBloom L3

Question

The tangent drawn from the origin to the circle $x^{2} + y^{2} + 2gx + 2fy + f^{2} = 0$ are perpendicular, if:

Options

A.$g = f$
B.$g = - f$
C.$g = 2f$
D.$2g = f$

Solution

Sol. [Key Concept: Tangents from the origin to $x^{2} + y^{2} + 2gx + 2fy + f^{2} = 0$ are perpendicular when the origin lies on the director circle, giving $g = \pm \ f$ (the $f^{2}$ makes it touch an axis).]

$$\begin{matrix} \sqrt{g^{2} + f^{2}} & \ = \frac{\sqrt{g^{2} + f^{2} - f^{2}}}{sin45^{\circ}} \\ \Rightarrow \ g^{2} + f^{2} & \ = 2(g)^{2} \\ g^{2} & \ = f^{2} \Rightarrow g = \pm f \end{matrix}$$

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