CircleHardBloom L3

Question

The locus of the center of the circles such that the point $(2,3)$ is the mid point of the chord $5x + 2y = 16$ is:

Options

A.$2x - 5y + 11 = 0$
B.$2x + 5y - 11 = 0$
C.$2x + 5y + 11 = 0$
D.none of these

Solution

Sol. [Key Concept: Locus of the centre with $(2,3)$ the midpoint of a chord: use the midpoint-chord relation $T = S_{1}$.]

$$\begin{matrix} & \frac{k - 3}{h - 2} = \frac{2}{5} \\ & 5k = 2h + 11 \\ & 2x - 5y + 11 = 0 \end{matrix}$$

Create a free account to view solution

View Solution Free
Topic: Circle·Practice all Circle questions

More Circle Questions